All categories

3 years ago

What is the sign of the product (−4)(2)(−3)(6)?

Mathematics

2 answers:

Whitepunk [10]3 years ago

6 0

Answer:

-144

Step-by-step explanation:

solong [7]3 years ago

5 0

Answer: negative ; -144 sowwy if im wrong

Step-by-step explanation:

-4, 2, -3 , 6

-4 times -3 = -12

6 times 2 = 12

-12 times 12 = -144

You might be interested in

Which equation in point-slope form contains the point (–3, 5) and has slope –1? y + 3 = –1(x – 5) y – 5 = –1(x + 3) y – 3 = –1(x

andreev551 [17]

Answer:

y - 5 = -1(x + 3)

Step-by-step explanation:

Point slope form

y - y1 = m(x - x1) where m = slope and passing through point (x1 , y1)

In this case if the equation in point-slope form contains the point (–3, 5) and has slope –1 then the equation should be:

y - 5 = -1(x - (-3))

y - 5 = -1(x + 3)

5 0

3 years ago

Use the intermediate value theorem to choose an interval over which the function, f(x)=2x^3 - 3x +5 is guaranteed to have a zero

Sergio039 [100]

Answer:

The answer is c. {0,2).

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write the fraction as the sum of two fractions with the same denominator

grandymaker [24]

1/4 + 1/4 = 1/2

I got 1/2 because if you add 1/4 and 1/4 you'd get 2/4, and when you simplify 2/4 you'd get 1/2.

3 0

3 years ago

What is the function form for 2x + 3y = 12

valina [46]

2x+3y=12
Subtract by 2x
3y=-2x+12
Divide by 3
y=-2/3x+4

4 0

3 years ago

Read 2 more answers

Situation D: Suppose that, in a one-minute period during an electrical storm, the number of lightning strikes on a radar antenna

Crank

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 2.40$

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177$

21.77% probability that the antenna will be struck exactly once during this time period.

3 0

3 years ago