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2 years ago

HELP ME PLEASE!!!!!!!

Mathematics

2 answers:

Bess [88]2 years ago

7 0

The answer is y=-3 ur welcome

inysia [295]2 years ago

3 0

Here you go :) I sent the work in the picture below

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Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

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Subtract y from both sides:

$x=5-y$

Now, substitute "5-y" for "x" in the first equation:

$(5-y)^2-y^2=100$

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Cancel out like terms:

$25-10y=100$

Subtract 25 from both sides:

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Divide both sides by -10

$y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}$

Now, substitute this value back into either of the equations to solve for x.

$x+y=5\\x-\frac{15}{2}=5\\$

Add 15/2 to both sides:

$x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}$

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