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3 years ago

Simplify by dividing negative three over eight ÷ five over nine

Mathematics

1 answer:

sleet_krkn [62]3 years ago

8 0

Answer:

Exact form : - 27/40

Decimal form : -0.675

Step-by-step explanation: Reduce the expression, if possible, by cancelling the common factors.

I hope this helps you out! :)

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In a game of checkers there are 12 red pieces and 12 black game pieces.Julio is setting up the board to begin playing. what is t

Bond [772]

Since there are equal numbers of pieces, the chances of Julio getting a red on the first pull is 12/24 or 1/2 (reduced)

However on the second pull there are only 11 reds (Julio pulled one out) out of 23 remaining pieces so the chances of pulling the second red are 11/23

Now multiply those possibilities:
1/2 x 11/23 and you will get 11/46 which is the probability of pulling two reds in a row. 11/46 is the answer.

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2 years ago

The manager of a warehouse would like to know how many errors are made when a product’s serial number is read by a bar-code read

maw [93]

<span>In order to determine the total number of errors that were made by the bar code scanner, we first have to calculate how many total scans were made. Because there were six items scanned 1,000 times each, there were 6,000 total scans made. Next, we have to add up the total number of errors made by each item (36+14+21+39+11+2). As a result, there were a total of 123 errors made during the 6,000 scans.</span>

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3 years ago

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2.57 as a improper fraction

USPshnik [31]

Answer: 2 57/100 hope that helps

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3 years ago

In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th

WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ; 10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, $\frac{dx}{dt}$ = $1,000

Now,

a) computers per household are

since,

mean income of $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

q = 0.5198 computers per household

b) Rate of increase in computers i.e $\frac{dq}{dt}$

$\frac{dq}{dt}$ = $\frac{d(0.3458 ln x - 3.045)}{dt}$

$\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0$

on substituting the values, we get

$\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000$

= 0.01153 computers

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3 years ago

How would write 42 as an operation???

ArbitrLikvidat [17]

I don't really get your question. But, I will try my best to answer it. 42 is a whole number and you could use the number for any operation.

I hope this helps:)

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2 years ago

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