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3 years ago

It'd be great if someone could help me on this!

Mathematics

2 answers:

Sever21 [200]3 years ago

6 0

Answer: 144 cubic feet

Step-by-step explanation:

Volume = base times height.

Base = 20 square feet

Height = 7.2 feet

Volume = 20 square feet * 7.2 feet = 144 cubic feet

Mademuasel [1]3 years ago

3 0

Answer: 144 square feet

Step-by-step explanation:

volume = length x width x height

volume = area x height

v = 20 x 7.2 = 144

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the units digit of a two-digit number is twice the tens digit. If the digits are reversed, the new number is 9 less than the ori

Anton [14]

Answer:

Step-by-step explanation:

Here is the correct and complete question: The units digit of a two-digit number is twice the tens digit. If the digits are reversed, the new number is 9 less than twice the original number. What is the original number?

Lets assume the original number be"10y+x". (x is unit digit and y is 10th digit)

∴ if number is reversed then resulting number be "10x+y".

As given: x= 2y

and $10x+y= 2(10y+x)-9$

Now, solving the equation to get original number.

$10x+y= 2(10y+x)-9$

Distributing 2 to 10y and x, then opening the parenthesis.

⇒ $10x+y= 20y+2x-9$

subtracting by (2x+y) on both side.

⇒ $8x= 19y-9$

subtituting the value of "x", which is equal to 2y.

∴ $8\times 2y= 19y-9$

⇒ $16y=19y-9$

subtracting both side by (16y-9)

⇒ $3y= 9$

cross multiplying

We get, $y= 3$

y=3

∵x= 2y

$x=2\times 3= 6$

∴ x= 6

Therefore, the original number will be 36 as x is the unit number and y as tenth number.

6 0

3 years ago

For all real numbers x and y, if x # y = x(x-y), then x # (x # y) =

kati45 [8]

$x\#y=x(x-y)\\\\x\#(x\#y)\\\\x\#y=x(x-y)=x^2-xy\\\\x\#(x\#y)=x\#(x^2-xy)=x[x-(x^2-xy)]=x(x-x^2+xy)\\\\=x^2-x^3+x^2y$

$x^2-x^3+x^2y=8\\\\x^2(1-x+y)=8\\\\x^2(1-x+y)=2^2\cdot4\iff x^2=2^2\ and\ 1-x+y=4\\\\x=2\ and\ y=4-1+x\\\\x=2\ and\ y=3+2\\\\x=2\ and\ y=5$

8 0

3 years ago

Read 2 more answers

What’s 1 plus 1 please hurrt

Aleks04 [339]

1+1 is equal to 2 lol

5 0

3 years ago

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Prove Euler's identity using Euler's formula.<br> e^ix = cos x + i sin x

Korolek [52]

First list all the terms out.

e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...

Then, we can expand them.

e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...

Then, we can use the rules of raising i to a power.

e^ix = 1 + ix - x^2/2! - ix^3/3!...

Then, we can sort all the real and imaginary terms.

e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)

We can simplify this.

e^ix = cos x + i sin x

This is Euler's Formula.

What happens if we put in pi?

x = pi

e^i*pi = cos(pi) + i sin(pi)

cos(pi) = -1

i sin(pi) = 0

e^i*pi = -1 OR e^i*pi + 1 = 0

That is Euler's identity.

3 0

3 years ago

A bag contains 11 tiles, one for each of the letters in the word BLUEBERRIES. You randomly choose a tile.

wel

2/11

there’s 2 R’s and 11 total so

possible outcomes/ overall outcomes

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3 years ago