Integers between -4 and 0 are : -3, -2, and -1
A. f(b) = 3+b
b. f(x) = (x+3)²
c. f(x) = (x+3)/(12-x)
d. f(x) = x⁵-4x+6
e. f(x) = -45
f. f(x) = x
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X=-1 and y=3
To solve this, because y is equal to 2x+5, you can substitute 2x+5 into the bottom equation for y.
You now have 3x - (2x + 5) =-6
This can be solved like a normal equation. Multiply each term in the parenthesis by -1.
3x - 2x - 5 = -6
Subtract 2x from 3x
x - 5 = -6
Add 5 to both sides
x=-1
Now you can solve for y by plugging -1 in for x in either equation. Im going to use the top one.
y= 2(-1)+5
y= -2+5
y=3
You can check your answer by plugging in the values for x and y into both equations and making sure both sides equal each other.
I think it might be expression one =14 i think and number 2 is obviously is 19 but you would put parenthesis around 5+4_2+6
I think i did this right its been a while since i did this
