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marta [7]
3 years ago
6

Can someone help me with this question please.

Mathematics
1 answer:
Daniel [21]3 years ago
7 0
For part A. 0.85

For part b. 11.9


Explain


Cost of each track in album A= total cost downloading album a/ total number of track


The problem give us a has 11 trackers and the total cost of download is 9.35 pounds


9.35/11

= 0.85


Now we are given each track cost in album b cost the same as track on A

Cost of each track in album B is 0.85

Now we are given if Jane download album B , B will be 14 tracks


Total cost of downloading is album B= number of tracks in album Bx cost of each track in album B


14x0.85 pound

= 11.9

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natulia [17]

Answer:

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Step-by-step explanation:

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Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.
lakkis [162]

Answer:

2*sin(x)+y*cos(x)-cos(y)=C_1

Step-by-step explanation:

Let:

P(x,y)=2*cos(x)-y*sin(x)

Q(x,y)=cos(x)+sin(y)

This is an exact differential equation because:

\frac{\partial P(x,y)}{\partial y} =-sin(x)

\frac{\partial Q(x,y)}{\partial x}=-sin(x)

With this in mind let's define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x}=P(x,y)

and

\frac{\partial f(x,y)}{\partial y}=Q(x,y)

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y)

f(x,y)=\int\  2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}

Now, let's replace the previous result into \frac{\partial f(x,y)}{\partial y}=Q(x,y) :

cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)

Solving for \frac{dg(y)}{dy}

\frac{dg(y)}{dy}=sin(y)

Integrating both sides with respect to y:

g(y)=\int\ sin(y)  \, dy =-cos(y)

Replacing this result into f(x,y)

f(x,y)=2*sin(x)+y*cos(x)-cos(y)

Finally the solution is f(x,y)=C1 :

2*sin(x)+y*cos(x)-cos(y)=C_1

7 0
3 years ago
Consider these numbers, ordered from least to greatest. Negative 1.8, negative 1 and one-fourth, negative 0.2, blank, one-half,
netineya [11]

Answer:

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Step-by-step explanation:

7 1
3 years ago
Read 3 more answers
Please answer this correctly
musickatia [10]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title
kirill [66]
y' = \frac{dy}{dx}

seperable differential equations will have the form
\frac{dy}{dx} = F(x) G(y)

what you do from here is isolate all the y terms on one side and all the X terms on the other
\frac{dy}{G(y)} = F(x) dx
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
\int \frac{1}{G(y)} dy = \int F(x) dx&#10;&#10;

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it


In your problem,
G(y) = \sqrt{1-y^2}&#10;&#10;F(x) = 2x

so all you need to integrate is
\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx
5 0
3 years ago
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