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Anni [7]
3 years ago
9

How do I solve for X

Mathematics
1 answer:
natulia [17]3 years ago
8 0
I believe you would solve for X like: 3x-10=2x-10.
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(9x+4)-42+83=1<br> Im confused
Umnica [9.8K]

Answer:

x=44/9 or 4 8/9

Step-by-step explanation:

4 0
2 years ago
Translate the sentence into an equation.
11Alexandr11 [23.1K]
Twice (2 times) the difference (subtraction) of a number (y) and 7 equals 3.

2*(y-7) = 3

hope this helps :)
4 0
4 years ago
Is there a formula for problems like these? How do I even begin to solve it?
Pachacha [2.7K]
Well, they're saying 9 with an exponet of 2 multiplied by something equals 27..... Hmmm.....
5 0
3 years ago
A plant costs p dollars and a bush costs b dollars. Ana buys 2 plants and 4 bushes for $42. Paola buys 7 plants and 9 bushes for
gregori [183]

Answer:

p = 5 and b = 8

Step-by-step explanation:

First, create a system of equations:

2p + 4b = 42

7p + 9b = 107

Solve by elimination by multiplying the top equation by -7 and the bottom equation by 2:

-14p - 28b = -294

14p + 18b = 214

Add these together, and solve for b:

-10b = -80

b = 8

Plug in 8 as b into one of the equations, and solve for p:

2p + 4b = 42

2p + 4(8) = 42

2p + 32 = 42

2p = 10

p = 5

So, p = 5 and b = 8

4 0
3 years ago
Read 2 more answers
(Will award Fast Brainliest &amp; Many Points!)
Softa [21]

Answer:

A] The slope of f(x) is greater than the slope of g(x).

Step-by-step explanation:

First, you need to calculate the slope of f(x) and g(x) using the slope formula

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are points of the functions.

To calculate the slope of f(x) you can choose two points from the graph, in this case (0, -1) and (3, 1). Remember you can choose the points you want as long they are on the graph.

m = 1 - (-1) / 3 - 0

m = 1 + 1 / 3

m = 2 / 3

m = 0.66...

To calculate the slope of g(x) you can choose two points from the table, in this case (0, 2) and (5, 4).

m = 4 - 2 / 5 - 0

m = 2 / 5

m = 0.4

So the slope of f(x) is greater than the slope of g(x).

3 0
3 years ago
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