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Lapatulllka [165]
3 years ago
9

Given: ABCD is a trapezoid, AC ⊥ CD , AB = CD, AC= square root of 75 , AB = 5 Find: Area of ABCD

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

How can its diagonal be perpendicular to one of its sides? Since this can be read out of your details! You know point A and C are not adjacent but C and D are. So, AC must be the diagonal which is never perp. to any of the sides (CD)
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One side of a square measures 6 centimeters. How tall is your area?
fgiga [73]

Area is side times side

One side = 6 cm

Area= 6×6= 36cm squared.

6 0
3 years ago
Solve the proportion below. 7/x=19
alexgriva [62]

Answer:

The value of x is approximately 0.3684.

Step-by-step explanation:

Given:

\frac{7}x}=19

We need to solve the proportion.

Solution:

Now we can see that;

In given equation one number is fraction and other number is whole number.

Now To make whole number into fraction we will divide by 1.

hence the whole number will be equal to;

19=\frac{19}{1}

Now the new equation will be;

\frac{7}{x}=\frac{19}{1}

Now by cross multiplication we get;

7\times1=19\times x\\\\7=19x

Now dividing both side by 19 we get;

\frac{7}{19}=\frac{19x}{19}\\\\x\approx0.3684

Hence the value of x is approximately 0.3684.

6 0
3 years ago
A group of adults plus one child attend a movie at a movie theater. Tickets cost $9 for adults and $3 for children. The total co
dmitriy555 [2]

Answer:

There are 6 adults. <em>My mistake! I had the wrong equation. 3 + 9a = 57.</em>

Step-by-step explanation:

  • <u>There is only 1 child in the group.</u>
  • Cost for children is 3$.
  • <u>The cost for adults is 9$.</u>
  • 9 * 6 = 54
  • 3 * 1 = 3
  • 3 + 9a = 57
  • Simplify:
  • 6 Adults.
8 0
2 years ago
Read 2 more answers
Please help me with this
Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }

Thefore the required answer is ,

\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}

4 0
2 years ago
Read 2 more answers
Pls help with this division
Vladimir [108]

x^2+3x+6

Step-by-step explanation:

this is the answer I got for some reason it is not an option on your question

6 0
3 years ago
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