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Lapatulllka [165]
3 years ago
9

Given: ABCD is a trapezoid, AC ⊥ CD , AB = CD, AC= square root of 75 , AB = 5 Find: Area of ABCD

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

How can its diagonal be perpendicular to one of its sides? Since this can be read out of your details! You know point A and C are not adjacent but C and D are. So, AC must be the diagonal which is never perp. to any of the sides (CD)
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The angles shown in the illustration are complementary. the measure of the larger angle is 30° more than three times the measure
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Smaller angle is 15, larger angle is 75.
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Eduardo has 24$ saved . if he saves 8$ each week how much money will he in 5 weeks .
lyudmila [28]

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is you are not adding in the 24 then 40 if you are adding in the 24 then 64

Step-by-step explanation:

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for two functions, a(x) and b(x), a statement is made that a(x) = b(x) at x=2. what is definitely true about x=2
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Functions a(x) and b(x) intersect each other at x = 2.

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What steps are involved in multiplying and dividing rational expressions?
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Answer:

Q and S do not equal 0.

Step 1: Factor both the numerator and the denominator. ...

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Step 3: Simplify the rational expression. ...

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Step-by-step explanation:

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7 0
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Nationwide, it is estimated that 40% of service stations have gas tanks that leak to some extent. A new program in California is
fredd [130]

Answer:

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

Step-by-step explanation:

The sample proportion is p2= 7/27= 0.259

and q2= 0.74

The sample size = n= 27

The population proportion = p1= 0.4

q1= 0.6

We formulate the null and alternate hypotheses that the new program is effective

H0: p2> p1   vs  Ha: p2 ≤ p1

The test statistic is

z= p2- p1/√ p1q1/n

z= 0.259-0.4/ √0.4*0.6/27

z=  -0.141/0.09428

z= -1.496

The significance level ∝ is 0.05

The critical region for one tailed test is z ≤ ± 1.645

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

8 0
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