1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka57 [31]
3 years ago
11

Can anyone help me please i will give you 15 points

Mathematics
1 answer:
romanna [79]3 years ago
3 0

Answer:

The answer is 17/20

Step-by-step explanation:

You might be interested in
The length of a rectangle is 2/5 its width and the perimeter is 280 inches, what are the length and width of the rectangle?
bogdanovich [222]
If the length is 2/5, or .40, then:

280/.40= 700

Check my answer:

.40*700= 280

The length is .40 (or 2/5) the width is 700.

I hope this helped!
6 0
3 years ago
A cube can be unfolded into the net shown below. Find the total
melisa1 [442]

Answer:

23.9 mm

Step-by-step explanation:

A cube can be unfolded into the net shown below. Find the total

surface area of the cube.

23.9 mm

7 0
3 years ago
The monthly revenue of a certain company is given by R 820p-7p, where p is the price in dollars of the product the company manuf
lora16 [44]

The revenue will be 12,000 when the price of the product  is $100

Given :

The monthly revenue of a certain company

R=820p-7p^2

We need to find out p when <u>Revenue R is 12000</u>

Lets replace R with 12000 and solve for p

12000=820p-7p^2\\820p-7p^2=12000\\-7p^2+820p-12000=0

Apply <em>quadratic formula </em>

p=\frac{-820\pm \sqrt{820^2-4\left(-7\right)\left(-12000\right)}}{2\left(-7\right)}\\p=\frac{-820\pm \:580}{2\left(-7\right)}\\p=\frac{-820+580}{2\left(-7\right)},\:p=\frac{-820-580}{2\left(-7\right)}\\p=\frac{120}{7},\:p=100

Given that price must be greater than 50

So the revenue will be 12000 when the price of the product  is $100

Learn more :  brainly.com/question/21503855

5 0
2 years ago
How would you determine what fraction strips with rhe same denominator would fit exactly under 1/2 &amp; 1/3. What are they?
vfiekz [6]

Step-by-step explanation:

\frac{1}{2}  =  \frac{1 \times 3}{2 \times 3}  =  \frac{1}{6}  \\  \\  \frac{1}{3} =  \frac{1 \times 2}{3 \times 2}   =  \frac{1}{6}

{ \boxed{{ \bold{{ \pink{e}}{ \blue{x}}{ \purple{p}}{ \green{l}}{ \red{a}}n{ \purple{a}}{ \orange{t}}{ \red{i}}on}}}}

  • we equate first under the fraction (denominator)
  • find the number of products that allow the denominators to be the same
  • the result that both fractions have the same denominator

<h3>Answer Details</h3>
  • Lesson : Math
  • Grade : 4

#I hope this helps°^°

6 0
3 years ago
It takes Megan 36 minutes to drive to the grocery store after work, which is 4/7 of the time it takes her to go directly home af
finlep [7]

Answer: 63 mins

Step-by-step explanation:

First you got to figure out how many minutes each 1/7 is, so you devide 4 into 36 which is 9. Now that you know each 1/7 is 9 you just multiply 9•7=63

8 0
3 years ago
Read 2 more answers
Other questions:
  • If f(x) = 2x2 - 5 and g(x) = x2 - 4x - 8, find (f - g)(x).
    5·1 answer
  • Find the HCF and LCM of<br> 20 and 38
    10·2 answers
  • trevor bought 8 gallons of paint to paint his house he used all but 1 quart how many quarts of paint did trevor used
    8·1 answer
  • Katie made a scale drawing of a painting in The Mint Museum of Art that was 2 ft by 3 ft choose the scale factor of 1/6 what are
    10·1 answer
  • Is the number 8.25 a rational number or an irrational number
    10·2 answers
  • Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
    6·1 answer
  • $850 flat fee for 31 to 50 guests
    13·1 answer
  • Tim runs 3 miles every 45 minutes. At this rate, how long did it take Tim to run 18 miles?
    10·1 answer
  • Please help!!!!!!!!!!
    11·1 answer
  • An airplane traveled 5.7 x 10 to the 2nd miles per hour for 1.4 x 10 to the 1st power hours. How far did the airplane travel
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!