They're all similar. Problem one you need to think how can I eliminate one of the variables to solve for the other one. Think muliplication in your head when doing this but as same time look for a way to subtract the variable you are eliminatiing should equal 0 then you solve the varialbe by itself. After you find one variables solution you need to substitute that solution into the variables place from one of the two original equations. I would think multiplying the -2y by 3 and 3y by 2. Notice one has a negative and other is positive so when I add the two equations I'll get 0y. However do not forget to multiply both equations by the multiplied number you used to each term in the equation. you should get 35x = 35 then x=1. Now you need to find y by substituting the 1 for either x-value in the two equations such as 4(1) + 3y = -5 now just solve for y and you get y = -3. your answer should be (1, -3). Notice you can always check and verify your right by substituting your values found into both solutions to get 15 = 15 and -5 = -5.
Answer:
![[3, 4]](https://tex.z-dn.net/?f=%5B3%2C%204%5D)
Step-by-step explanation:
{5x + 2y = 23
{13x + 3y = 51
−5⁄13[13x + 3y = 51]
{5x + 2y = 23
{−5x - 1 2⁄13y = 19 8⁄13 >> New Equation
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11⁄13y = 3 5⁄13
_____ ______
11⁄13 11⁄13
[Plug this back into both equations above to get the x-coordinate of 3]; 
I am joyous to assist you anytime.
You see the 2 squares or whatever multiply them one by one so
D be it’s all the great number for it
Answer:
SA= 2(l x w) |+2(l x h)+2(h x w)
= 2(14 x 12.4) +2(14 x 1)+2(1x 12.4)
=2(173.6)+2(14)+2(12.4)
=347.2|+28+24.8
Surface area is: 400 cm square
Step-by-step explanation:
