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belka [17]
4 years ago
5

How do you work this out? need help asap

Mathematics
1 answer:
Svetlanka [38]4 years ago
6 0
Hello,

Line 1 is passing through (-4,3), (-2,7) has a slope of (3-7)/(-4+2)=2

Line 2 is passing through (2,9), (4,1) has a slope of (9-1)/(2-4)=-4

One other way:

y=9-1/2 x²
y'=-x

gradient 1=-(-2)=2 for point (-2,7)

gradient 2=-(4)=-4 for point(4,1)



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A shirt is 39 dolars and on sale for 33% off and what is the discount and sale price
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4 0
3 years ago
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Nikitich [7]

Answer:

\frac{5x-4}{x(x^2+7)^2}  = \frac{A}{x} + \frac{Bx+C}{x^2+7} + \frac{Dx+E}{(x^2+7)^2}

Step-by-step explanation:

Given the expression \frac{5x-4}{x(x^2+7)^2}, we are to re-write the expression in form of a partial fraction.

Before we write in form of a partial fraction, we need to note the expression at the denominator. <u>Since the expression in parenthesis is a quadratic equation, the equivalent numerator must be a linear expression.</u>

<u />

<u>Also the quadratic equation is a repeated form since it is squared</u>. This means that we are to repeat the quadratic equation twice when writing as a partial fraction.

\frac{5x-4}{x(x^2+7)^2}  = \frac{A}{x} + \frac{Bx+C}{x^2+7} + \frac{Dx+E}{(x^2+7)^2}

From the above partial fraction, <em>it can be seen that x² + 7 in parenthesis was repeated twice and their equivalent expressions at the numerator are  both linear i.e Bx+E and Dx+ E where A, B, C, D and E are the unknown constant.</em>

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