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belka [17]
3 years ago
5

How do you work this out? need help asap

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0
Hello,

Line 1 is passing through (-4,3), (-2,7) has a slope of (3-7)/(-4+2)=2

Line 2 is passing through (2,9), (4,1) has a slope of (9-1)/(2-4)=-4

One other way:

y=9-1/2 x²
y'=-x

gradient 1=-(-2)=2 for point (-2,7)

gradient 2=-(4)=-4 for point(4,1)



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2. Which of the following are terms of the series with nth term T-3n +17? a) 80 b) 170 c)217 d) 312 e) 278 f) 3566
pishuonlain [190]

Answer:

The correct options are a,b,e and f.

Step-by-step explanation:

It is given that the nth terms of the series is defined as

T_n=3n+17

Subtract 17 from both the sides.

T_n-17=3n

Divide both sides by 3.

\frac{T_n-17}{3}=n

The term Tₙ is a term of given series if n is a positive integer.

(a) The given term is 80.

n=\frac{80-17}{3}=21

Since n is a positive integer, therefore 80 is a term of given series.

(b) The given term is 170.

n=\frac{170-17}{3}=51

Since n is a positive integer, therefore 170 is a term of given series.

(c) The given term is 217.

n=\frac{217-17}{3}=66.67

Since n is not a positive integer, therefore 217 is a term of given series.

(d) The given term is 312.

n=\frac{312-17}{3}=98.33

Since n is not a positive integer, therefore 312 is a term of given series.

(e) The given term is 278.

n=\frac{278-17}{3}=87

Since n is a positive integer, therefore 278 is a term of given series.

(f) The given term is 3566.

n=\frac{3566-17}{3}=1183

Since n is a positive integer, therefore 3566 is a term of given series.

Thus, the correct options are a, b, e and f.

7 0
3 years ago
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