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3 years ago

Please I need help Question: What are the solutions to this graph?

Mathematics

1 answer:

I am Lyosha [343]3 years ago

5 0

Answer:

The solution to the graph are x = -2 and x = 2

Step-by-step explanation:

Here, we want to get the solution to the graph

As we can see, the graph is parabolic; which is a property of a quadratic polynomial

The solution refers to the value at which the graph plot crosses the x-axis

In other words, the solutions to the graph are represented by the point at which we have the graph crossing over the x-axis

We can see this happen at two points

These are the points x = -2 and x = 2

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The perimeter of the rectangle below is 176 units. Find the length of side QR.

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Answer:

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Step-by-step explanation:

in a rectangle, opposite sides are equal

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3 years ago

The the slope of a line is 2. Use the coordinates (3,10) of the labeled point to find the point slope equation of the line.How?

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$\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s$

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