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Akimi4 [234]
4 years ago
14

The area of a triangle is 40 square inches. its base is 20 inches. find the altitude

Mathematics
2 answers:
Lorico [155]4 years ago
6 0

Answer:

4

Step-by-step explanation:

Nadya [2.5K]4 years ago
4 0

Answer: The altitude is 4

Step-by-step explanation:

Once you know the area, you have to work backwards. I flipped the area equation to solve for height and got 2A/b = h. After that I plugged in the numbers and got an altitude of 4.

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the answer is a octagon that has rotation of 45degrees

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How many solutions are there to the equation below?<br>12x + 32 = 12X-7​
Greeley [361]

Answer: no solutions

Step-by-step explanation:

12x+32=12x-7

12x-12x=-7-32

0x=-39

No solutions

5 0
3 years ago
How many one-thirds are there in three-fourths?
kumpel [21]

Answer:

there are 2.25 one-thirds in a three-fourth.

Hope this helps you out!

7 0
3 years ago
Read 2 more answers
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
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