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kap26 [50]
3 years ago
5

All questions to be solved using linear combination.

Mathematics
1 answer:
monitta3 years ago
8 0
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
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Help please . thank you
S_A_V [24]
PLEASE DONT USE THAT LINK
5 0
3 years ago
Write the slope-intercept form of an equation of the line that passes through the given point and is parallel to the graph of ea
koban [17]

Answer:

slope(m)=5/4 and

y-intercept (c)=12

Step-by-step explanation:

here,given equation of a line is

5x-4y-1=0...eqn(i)

equation of any line parallel to line(i) is

5x-4y+k=0...eqn(ii)

since,the line(ii) passes through (-8,2)[replacing x=-8 and y=2 in eqn(ii), we get]

5*(-8)-4*2+k=0

or-40-8+k=0

•°•k=48

substituting the value of k=48 in eqn(ii),

5x-4y+48=0 is the required equation of the line.

now,

changing eqn(ii) in slope intercept form we get,

4y=5x+48

or,y=5x/4+48/4

or,y=(5/4)x+12

comparing it into y=mx+c we get,

slope(m)=5/4 and y-intercept(c)=12

6 0
3 years ago
MARKING BRAINIEST ANSWER!!!
cluponka [151]

Answer:

y = 3

Step-by-step explanation:

Hello,

f(x)=(\dfrac{1}{2})^x+3

when x tends to +\infty

(1/2)^x tends to 0 as 1/2 < 1

so the equation of the asymptote for this function is y = 3

3 0
3 years ago
Read 2 more answers
Find the value of x and the length of each side—- geometry
gizmo_the_mogwai [7]

Answer:

I think x = 7

but I'm not sure

.. :-))

3 0
2 years ago
Solve with explanation please
Reil [10]

Answer: \boxed{\dfrac{2}{5}}

f(3)

Put the value of x = 3 to the equation of the function

f(x)=\dfrac{4}{5}x-2\\\\f(3)=\dfrac{4}{5}\cdot3-2=\dfrac{4\cdot3}{5}-2=\dfrac{12}{5}-\dfrac{10}{5}=\dfrac{12-10}{5}=\boxed{\dfrac{2}{5}}

7 0
3 years ago
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