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aksik [14]
4 years ago
12

Given a rhombus, a square, and a rectangle, what must be true of all three quadrilaterals?

Mathematics
1 answer:
Yuliya22 [10]4 years ago
8 0
<span>C.

The diagonals are perpendicular.
</span>
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Linar system in variables<br> -x-3y-2z=8,<br> -x+y+6z=, <br> x-9y-2z=4
docker41 [41]

Answer:

-x+y+6z=? You did not spcify so I just made it 0

x = -22/5, y = -4/5, z = -3/5

Step-by-step explanation:

Solve the following system:

{-x - 3 y - 2 z = 8 | (equation 1)

-x + y + 6 z = 0 | (equation 2)

x - 9 y - 2 z = 4 | (equation 3)

Subtract equation 1 from equation 2:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x+4 y + 8 z = -8 | (equation 2)

x - 9 y - 2 z = 4 | (equation 3)

Divide equation 2 by 4:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x+y + 2 z = -2 | (equation 2)

x - 9 y - 2 z = 4 | (equation 3)

Add equation 1 to equation 3:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x+y + 2 z = -2 | (equation 2)

0 x - 12 y - 4 z = 12 | (equation 3)

Divide equation 3 by 4:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x+y + 2 z = -2 | (equation 2)

0 x - 3 y - z = 3 | (equation 3)

Swap equation 2 with equation 3:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x - 3 y - z = 3 | (equation 2)

0 x+y + 2 z = -2 | (equation 3)

Add 1/3 × (equation 2) to equation 3:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x - 3 y - z = 3 | (equation 2)

0 x+0 y+(5 z)/3 = -1 | (equation 3)

Multiply equation 3 by 3:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x - 3 y - z = 3 | (equation 2)

0 x+0 y+5 z = -3 | (equation 3)

Divide equation 3 by 5:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x - 3 y - z = 3 | (equation 2)

0 x+0 y+z = -3/5 | (equation 3)

Add equation 3 to equation 2:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x - 3 y+0 z = 12/5 | (equation 2)

0 x+0 y+z = -3/5 | (equation 3)

Divide equation 2 by -3:

{-x - 3 y - 2 z = 8 | (equation 1)

0 x+y+0 z = -4/5 | (equation 2)

0 x+0 y+z = -3/5 | (equation 3)

Add 3 × (equation 2) to equation 1:

{-x + 0 y - 2 z = 28/5 | (equation 1)

0 x+y+0 z = -4/5 | (equation 2)

0 x+0 y+z = -3/5 | (equation 3)

Add 2 × (equation 3) to equation 1:

{-x+0 y+0 z = 22/5 | (equation 1)

0 x+y+0 z = -4/5 | (equation 2)

0 x+0 y+z = -3/5 | (equation 3)

Multiply equation 1 by -1:

{x+0 y+0 z = -22/5 | (equation 1)

0 x+y+0 z = -4/5 | (equation 2)

0 x+0 y+z = -3/5 | (equation 3)

Collect results:

Answer: {x = -22/5, y = -4/5, z = -3/5

8 0
3 years ago
Sandi is 13 years old. Karla is 3 times Sandi's age. How old is Karla?
RoseWind [281]
39. 13x3.....................

7 0
3 years ago
8k + 2m = 3m + k<br><br> Solve for k
mina [271]
Minus both sides by 2m
8k = 3 m - 2m + k \\ 8k = m + k
Minus both sides by k
7k = m
Divided both sides by 7
k =  \frac{m}{7}
6 0
3 years ago
Which expressions are equivalent to 12r-5?
Gekata [30.6K]

Answer:

c

Step-by-step explanation:

because u cant be wrong with going with none of the above due the fact that they could be decimals and they didn't want to write out the full number therefore making it incorrect. No need to thank me.

7 0
3 years ago
-3(8n - 5) - 2n = 8n - 21
BigorU [14]

Answer:

Step-by-step explanation:

First you do the parentheses so the -3 x 8n= -24 and -3 x -5= 15

so it will look like this. -24n+15-2n=8n-21

Now combine like terms the -24n-2n.

-26n+15=8n-21 now subtract 8n now it will look like this

-34n+15=-21 now -15 from -21

-34n=-36

now if you want n by its self divide -34 and -36

7 0
3 years ago
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