3 years ago

Given a rhombus, a square, and a rectangle, what must be true of all three quadrilaterals?

Mathematics

1 answer:

Yuliya22 [10]3 years ago

8 0

<span>C.

The diagonals are perpendicular.
</span>

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In the diagram shown overline AD and intersect at point E. overline AB and overline CD are parallel . Given the segment length s

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Step-by-step explanation:

Since AB and CD are parallel, ∠D is congruent to ∠A and ∠C is congruent to ∠B. Therefore the two triangles are similar by the AA postulate. Now, the corresponding sides are in proportion

Since AE ↔ DE and AB ↔ CD

So, AE/CD = AB/CD

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The solution to the equation is x = 1.62

<h3>How to solve the equation?</h3>

The equation is given as:

$x =\sqrt{x\ -\ \frac{1}{x}}+\sqrt{1-\ \frac{1}{x}}$

Next, we split the equations as follows:

y = x

$y =\sqrt{x\ -\ \frac{1}{x}}+\sqrt{1-\ \frac{1}{x}}$

Next, we graph the equations (see attachment)

From the attached graph, the equations intersect at

(x, y)= (1.62, 1.62)

Remove the y value

x = 1.62

Hence, the solution to the equation is x = 1.62