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ohaa [14]
3 years ago
11

Amy runs 5 miles in 38 minutes how many miles would she run in 57 minutes?

Mathematics
1 answer:
Len [333]3 years ago
5 0
Amy runs 1 mile in 7.6 minutes so in 57 minutes she will have run 7.5 miles
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In the equation 0.75 - 5/8s = 44, how do your combine the like terms?
Mnenie [13.5K]

Answer:

and let's then do away with the denominators, by multiplying both sides by the LCD of all fractions, in this case, the LCD will be 8, and then we'll combine the like-terms, but anyway, let's proceed.

Step-by-step explanation:

3 0
3 years ago
Which of the following transformations will not always result in a congruent image?
Scorpion4ik [409]

Answer:

Step by step

A) Dilation

6 0
3 years ago
May someone please help me with 1-5? I have been stuck on this for a while now.​
AleksAgata [21]

Answer:

1 and 2 are correct!! Good Job!!

3. on the number line put a solid dot over 0, the line should to the right.

4. on the number line put a solid dot over -4, the line will go to the left.

5. on the number line put a open dot over 1.5, the line will go to the left.

Step-by-step explanation:

I hope this helps!! Also, you did great on 1 and 2, got this!!

5 0
3 years ago
At a school assembly four out of the first 10
Ilya [14]

Answer:

125

Step-by-step explanation:

Well if 10 x 50 is 500 (just to show how you get doesn't affect problem) you would simply divide by 4 thus, you get 125 (edit: sorry if this is wrong I'm in my first year of middle lol)

5 0
2 years ago
Answer ASAP. Please give correct answer. (Involves a bunch of circles and trig identities)
iren [92.7K]

Answer:

45.40

Step-by-step explanation:

First of all, the shape of rope is not a parabola but a catenary, and all catenaries are similar, defined by:

y=acoshxa

You just have to figure out where the origin is (see picture). The hight of the lowest point on the rope is 20 and the pole is 50 meters high. So the end point must be a+(50−20) above the x-axis. In other words (d/2,a+30) must be a point on the catenary:

a+30=acoshd2a(1)

The lenght of the catenary is given by the following formula (which can be proved easily):

s=asinhx2a−asinhx1a

where x1,x2 are x-cooridanates of ending points. In our case:

80=2asinhd2a

40=asinhd2a(2)

You have to solve the system of two equations, (1) and (2), with two unknowns (a,d). It's fairly straightforward.

Square (1) and (2) and subtract. You will get:

(a+30)2−402=a2

Calculate a from this equation, replace that value into (1) or (2) to evaluate d.

My calculation:

a=353≈11.67

d=703arccosh257≈45.40

7 0
3 years ago
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