Question

What are the roots of the equation x^2-3x+1=0

Answer 1

Answer:

$x=\frac{3+/-\sqrt{5} }{2}$

Step-by-step explanation:

To find the roots of the equation, factor the equation and set each factor equal to 0 or use the quadratic equations. The quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=-3, and c=1

$x=\frac{-(-3)+/-\sqrt{(-3)^2-4(1)(1)} }{2(1)} \\x=\frac{3+/-\sqrt{9-4)} }{2} \\x=\frac{3+/-\sqrt{5} }{2}$