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3 years ago

Jill is factoring the expression 13XY -52y. Her work is shown below

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

3 0

Answer:13y(x-4)

Step-by-step explanation:

13xy-52y =13y(x-4)

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The title of the homework is Sine and Cosine rule

Delicious77 [7]

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3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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3 years ago

What is the answer(FP!) 29/3 5/5 20/10 100/50

liubo4ka [24]

Answer:

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Step-by-step explanation:

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2 years ago

In the wrong hands, which of the following pieces of personal information would present the greatest risk for identity theft?

Aneli [31]

Answer:

D. social security number

Step-by-step explanation:

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Hope this will helpful.

Thank you.

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3 years ago

Read 2 more answers

3/2k - 9 = 1/8K + 2 I need to find what k is

gizmo_the_mogwai [7]

Answer:

= 8

Step-by-step explanation:

Combine multiplied terms into a single fraction

Multiply by 1

Add 9 to both sides of the equation

Simplify

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2 years ago