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3 years ago

Jill is factoring the expression 13XY -52y. Her work is shown below

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

3 0

Answer:13y(x-4)

Step-by-step explanation:

13xy-52y =13y(x-4)

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a runner warms up for ten minutes and then takes seven minutes to run each mile. the total time after r miles in 45 minutes. how

Alika [10]

45=10+7x
35=7x
5=x

Answer: they ran 5 miles

Hope this helps:)

6 0

3 years ago

Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?

irakobra [83]

First, note that $m\angle A+m\angle C=90^{\circ}.$ Then

$m\angle A=90^{\circ}-m\angle C \text{ and } m\angle C=90^{\circ}-m\angle A.$

Consider all options:

$\tan A=\dfrac{\sin A}{\sin C}$

By the definition,

$\tan A=\dfrac{BC}{AB},\\ \\\sin A=\dfrac{BC}{AC},\\ \\\sin C=\dfrac{AB}{AC}.$

Now

$\dfrac{\sin A}{\sin C}=\dfrac{\dfrac{BC}{AC}}{\dfrac{AB}{AC}}=\dfrac{BC}{AB}=\tan A.$

Option A is true.

$\cos A=\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan (90^{\circ}-A)=\dfrac{\sin(90^{\circ}-A)}{\cos(90^{\circ}-A)}=\dfrac{\sin C}{\cos C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AC}}=\dfrac{AB}{BC},\\ \\\sin (90^{\circ}-C)=\sin A=\dfrac{BC}{AC}.$

Then

$\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}=\dfrac{\dfrac{AB}{BC}}{\dfrac{BC}{AC}}=\dfrac{AB\cdot AC}{BC^2}\neq \dfrac{AB}{AC}.$

Option B is false.

$\sin C = \dfrac{\cos A}{\tan C}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

Now

$\dfrac{\cos A}{\tan C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{AB}{BC}}=\dfrac{BC}{AC}\neq \sin C.$

Option C is false.

$\cos A=\tan C.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

As you can see $\cos A\neq \tan C$ and option D is not true.

$\sin C = \dfrac{\cos(90^{\circ}-C)}{\tan A}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos (90^{\circ}-C)=\cos A=\dfrac{AB}{AC},\\ \\\tan A=\dfrac{BC}{AB}.$

Then

$\dfrac{\cos(90^{\circ}-C)}{\tan A}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AB}}=\dfrac{AB^2}{AC\cdot BC}\neq \sin C.$

This option is false.

8 0

3 years ago

Read 2 more answers

Mrs. Habib has 46.25 feet of border for a bulletin board for her classroom. the board is 37.5 feet tall and 8.3 feet wide. how m

otez555 [7]

Assuming that it is a square board, she would not have enough. This is because there would be twice as much height and twice as much width. Those numbers add up to far more.

However, if they just have to cover those two sides they will have 0.45 left. You can get this by subtracting the amounts from the overall.

46.25 - 37.5 - 8.3 = 0.45

3 0

4 years ago

Divide $800 between kofi and kweku so that kofi gets three times what kweku gets

AfilCa [17]

Answer:

600 and 200

Step-by-step explanation:

kofi : kweku is 3 :1

so Kofi gets 3 out of ( 3 +1) = 3/4 of 800 = 3/4 * 800 = 600

kweku get s the rest 800- 600 = 200

6 0

1 year ago

Simplify the following expression. 3 ^11/5 dived 3-^9/5

Helen [10]

Answer:

81 is the answer cause u just have to aolve the 3^11^5 first ana comes and divide with the answer ot 3^-9/5.

5 0

3 years ago