3 years ago

Consider this right triangle with given measures.

Mathematics

2 answers:

Viefleur [7K]3 years ago

8 0

It's two, three, and four.

Yes, I copied the person above me, but at least I checked in with the answers first.

lana [24]3 years ago

5 0

Answer:

Step-by-step explanation:

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Use the quadratic formula to find the solutions to the quadratic equation below x^2-6x-5=0

Sonja [21]

Answer:

$\large\boxed{x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}}$

Step-by-step explanation:

$x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}$