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Blizzard [7]
3 years ago
8

Emilio throws a marshmallow into the air from his balcony. The height of the marshmallow (in feet) is represented by the equatio

n h=−16t2+8t+48, where t is the time (in seconds) after he throws the marshmallow. How long does it take the marshmallow to hit the ground, where h=0?
Mathematics
1 answer:
irinina [24]3 years ago
4 0

Answer:

Step-by-step explanation:

The height of the marshmallow (in feet) is represented by the equation h=−16t2+8t+48,

where t is the time (in seconds) after he throws the marshmallow.

The equation is a quadratic equation. When the marshmallow hits the ground, its height from the ground will be zero. Therefore

−16t^2+8t+48 = 0

- 2t^2 + t + 6 = 0

Multiplying through by the negative sign. It becomes

2t^2 - t - 6 = 0

2t^2 + 3t - 4t - 6 = 0

t(2t + 3) - 2(2t + 3) = 0

(t - 2)(2t + 3) = 0

t - 2 = 0 or 2t + 3 = 0

t = 2 or t = - 3/2

The time cannot be negative

So it will take 2 seconds to hit the ground

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ΔA'B'C' is a reduction of ΔABC and ΔA'B'C' is similar to ΔABC.

Step-by-step explanation:

It is given that the triangle ABC is dilated to produce triangle A'B'C' with scale factor 3/4.

If a figure is dilated then preimage and image are similar.

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