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12345 [234]
3 years ago
14

What are the zeros of f(x)=(x-2)(3x+1)​

Mathematics
2 answers:
Snezhnost [94]3 years ago
7 0

Answer:

( x-2) ( 3x+1)

3x^2 + x - 6x - 2

x( 3x + 1 ) -2( 3x + 1 )

( 3x + 1 ) ( x - 2 )

either

3x + 1 = 0

3x = -1

x = -1/3

or

x - 2 = 0

x = 2

( -1/3 , 2 )

Basile [38]3 years ago
6 0

2,-  \frac{1}{3}

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Which equation is y = –3x2 – 12x – 2 rewritten in vertex form?
Andrej [43]
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(y- k)= a(x - h)^2

This could be done by using completing the square method.

</span><span>y = –3x^2 – 12x – 2
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3 0
4 years ago
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Which inequality has the solution shown below?<br> -18 -17 -16 -15 -14 -13 -12
dmitriy555 [2]

Answer:

0.2x+5>2

Step-by-step explanation:

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6 0
3 years ago
You can represent an odd integer whith the expression 2n+1, where n is any integer . Write and solve an equation to find three c
oksian1 [2.3K]
Any odd number can be expressed by 2n+1.

For example,  

2n+1=111
2n=110
n=110/2=55

means that 111 is 2n+1 for n=55


Thus if an odd number is 2a+1, the next few numbers are as follows:

2a+1, 2a+2, 2a+3, 2a+4, 2a+5

So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.


Back to our problem: 

three consecutive odd numbers whose sum is 63 are:

(2n+1)+(2n+3)+(2n+5)=63

6n+9=63

6n=63-9=54

n=54/6=9


2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23


Answer: 19, 21, 23



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3 years ago
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What’s the question you only gave me the answers?
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Elenna [48]

Answer:

reflection over the x-axis

Step-by-step explanation:

i hope this helps

6 0
3 years ago
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