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Vilka [71]
3 years ago
6

Read the situations in the table below. Then drag a graph and equation to represent

Mathematics
1 answer:
Natali [406]3 years ago
7 0

Answer:

Step-by-step explanation:

"Tamara runs 5 miles each week"

Let Tamara runs 'x' weeks then equation that represents the total distance covered by Tamara will be,

1). y = 5x

2). Here 'y' is directly proportional to the number of weeks 'x'.

3). And the graph when plotted will start from 0. Therefore, graph (1) will be the graph for the given equation.

"Tamara runs 5 minutes more than she walks each day."

1). If Tamara walks 'x' minutes daily and she runs for y minutes then relation between x and y will be,

y = x + 5

2). y and x are non proportional.

3). Graph will have y-intercept = 5

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Ms. Lorahs smartphone has 3.5 GB of free storage space, which is 27.5% of the total storage space on her smartphone. What is the
statuscvo [17]
12.73 GB total when rounded to the nearest 100th.

3.5/27.5=y

y•100= 12.73
4 0
3 years ago
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
3 years ago
What is the average rate of change from -3 to 0 of the function represented by the graph?
lbvjy [14]

Average rate of change = change in y ÷ change in x

We already know the change in x because we are measuring the x values from -3 to 0.

change in x = 0-(-3) = 3

To find the change in y find the difference between the corresponding y-values when x=0 and when x=-3.

change in y = 0.5-2 = -1.5

average rate of change = -1.5/3 = -0.5

answer: -0.5

3 0
3 years ago
Which equation is true? 0.9 = 9/100 , 1.9 = 9/100 , 12/10 = 1.2 , or 18/9 = 0.2?
weqwewe [10]

Answer:

12/10=1.2

Step-by-step explanation:

You just move the decimal one place value to the left. so 12÷10=1.2 which is the same as 12/10=1.2

6 0
3 years ago
Read 2 more answers
Does a linear equation have no solution, one solution, or infinitely many solutions?
Natasha_Volkova [10]
I think that a linear equation can have no solution, one solution, or infinitely solutions. It just depends on what is the equation. That's what I think

3 0
3 years ago
Read 2 more answers
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