Use the distributive property to remove the parentheses. -2 (-u-3x+2)
2 answers:
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Set up the given triangle on x-y coordinates with right angle at (0,0). So the two vertices are at (5,0) and (0,2![sqrt{x} n]{3}](https://tex.z-dn.net/?f=sqrt%7Bx%7D%20n%5D%7B3%7D%20)
)
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
smallest value happens at
so area is
hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
smallest value happens at
so area is
hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
By the law of cosines, the angle 
satisfies
which reduces to
which converts to approximately 77 degrees (this can be done my multiplying by 180 and dividing by pi).
which reduces to
which converts to approximately 77 degrees (this can be done my multiplying by 180 and dividing by pi).
Answer:
The average rate of change is -3.
Step-by-step explanation:
We are given the function:
And we want to find the average rate of change from <em>x </em>= 0 to <em>x </em>= 3.
In other words, we will compute the function at the two endpoints, and then find the slope of the line that crosses the two points.
For our first endpoint at <em>x</em> = 0, our function evaluates to:
So, our first point is (0, 9).
For our second endpoint at <em>x</em> = 3, our function evaluates to :
So, our second point is (3, 0).
Then by the slope formula, our average rate of change will be: