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aniked [119]
3 years ago
9

Which of the following is an example of theoretical probability?

Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

The correct answer is C. Kelli put 6 red marbles and 5 blue marbles in a bag. The probability of selecting a red marble is 6 /11

Explanation:

Theoretical probability occurs as you calculate the probability of a specific outcome in a situation, without experimenting or observing it. Because of this, the probability is theoretical rather than experimental. Also, you can know this, if you divide the number of specific favorable outcomes by the total of possible outcomes.

Option C shows a theoretical probability because this is the only case the probability has not been observed or experimented. Also, expressing the probability as 6/11 is completely correct because 6 is the total of red marbles(possible desired outcomes), while 11 is the total marbles (possible outcomes).

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Which two ratios form a proportion? A) 1 : 3 and 6 : 3 B) 1 : 3 and 3 : 6 C) 3 : 1 and 9 : 3 D) 3 : 1 and 3 : 9
tamaranim1 [39]

Answer:

c

Step-by-step explanation:

you have to set them up as a fraction and see if they are an equivalent fraction and if they are thats the proportion

4 0
3 years ago
Read 2 more answers
Solve the inequality and graph the solution.
Fofino [41]

Answer:

Step-by-step explanation:

5w - 8 ≥ 2

5w ≥ 10

w ≥ 2

closed circle at 2 going to the right

5 0
2 years ago
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10-root18/root2 = a+broot2
Sauron [17]

Step-by-step explanation:

\frac{10 -  \sqrt{18} }{ \sqrt{2} } = a + b \sqrt{2}

\frac{10}{ \sqrt{2} }   +  \frac{ -  \sqrt{18} }{ \sqrt{2} }

5 \sqrt{2}   + (  \frac{ -  \sqrt{18} }{ \sqrt{2} } ) \times  \sqrt{2}

a = 5 \sqrt{2}

b =  \frac{ -  \sqrt{18} }{ \sqrt{2} }

8 0
2 years ago
Answer the manager one
Blizzard [7]
256x24 is 6,144, so the manager ordered a total of 6,144 football cards.
4 0
3 years ago
The as x approaches 0 of tan^2x/x
uysha [10]

L=Lim tan(x)^2/x x->0

Since both numerator and denominator evaluate to zero, we could apply l'Hôpital rule by taking derivatives.

d(tan^2(x))/dx=2tan(x).d(tan(x))/dx = 2tan(x)sec^2(x)

d(x)/dx = 1

=>

L=2tan(x)sec^2(x)/1 x->0

= (2(0)/1^2)/1

=0/1

=0


Another way using series,

We know that tan(x) = x+x^3/3+2x^5/15+.....

then tan^2(x), using binomial expansion gives

x^2+2*x^4/3+.... (we only need two terms)

and again apply l'Hôpital's rule, we have

L=d(x^2+2x^4/3+...)/d(x) = (2x+8x^3/3+...)/1

=0 as x->0

3 0
3 years ago
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