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Eduardwww [97]
3 years ago
11

PLEASE HELP NEED TO KNOW IF IM CORRECT! WILL REWARD BRAINLIEST ANSWER!

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0
Using a^2 + b ^{2} = c^{2}
x²+12²=13²
x²=13²-12²
x²=169-144
x²=25
x=5

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What is 3 times 4 brodie:)
Nata [24]

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4 0
2 years ago
Which is better buy? 5 lb of flour for $0.90 or<br> 8 lb for $1.25
Ludmilka [50]
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4 0
3 years ago
Read 2 more answers
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
2 years ago
Marking brianliest pls help
Contact [7]

Answer:

117.3

Step-by-step explanation:

7*4=117.29=117.3

6 0
3 years ago
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