Question

the vertex form of the equation of a parabola is y=4(x-2)^2-1. what is the standard form of the equation?

Answer 1

Just expand the terms to get general form.

$y=4(x-2)^2-1 \\y=4(x-2)(x-2)-1 \\y=4(x^2-4x+8)-1 \\y=4x^2-16x+31$

Hope this helps.