Ask question

Ask question

All categories

1 year ago

13

A telemarketer spent 7 hours during her 8-hour shift calling up new clients. What percentage of her time was spent on things oth

er than working with new clients

1 answer:

padilas [110]1 year ago

6 0

1/8 of her time was spent on things other than working with clients. 1/8 = 0.125 * 100 = 12.5%

You might be interested in

Como puedo salir de Brainly

sergey [27]

Answer:

push the x on the top left corner of the tab

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find each product. <br> (x - 6)(x + 2)

emmainna [20.7K]

Answer:

x^2-4x-12

Step-by-step explanation:

(x-6)(x+2)=x^2-6x+2x-12=x^2-4x-12

6 0

2 years ago

Read 2 more answers

Are the graphs of the lines in the pair parallel? Explain.

jonny [76]

You need to convert the second equation to slope/intercept form. The first equation is in that form already. Then you can compare slopes.

-6x + 8y = 14
8y = 6x + 14
y = (3/4)x + 14/8

SO THE SLOPE IS 3/4 which is the same as slope of equation 1

Therfore they are parallel.

7 0

3 years ago

What is an algebraic expression for this word phrase?

snow_lady [41]

The first choice, 5+7n.

3 0

2 years ago

Help please I'm stuck show and explain your work

Deffense [45]

The expressions D, E, and F represent a correct solution to the equation.

Step-by-step explanation:

Step 1:

First, we need to solve the given equation and find the value of x which satisfies the equation.

$6(x+4)=20, (x+4) = \frac{20}{6} = 3.333,$

$x = 3.333 - 4 = -0.666.$

So the value of x for the given equation is -0.666.

Step 2:

Now we evaluate the values of the six given options to see which ones have an x value of -0.666.

A. $\frac{20-4}{6}= \frac{16}{6} = 2.666,$

B. $\frac{1}{6} (20-4)= \frac{1}{6} (16)=\frac{16}{6} = 2.666,$

C. 20 -6 -4 = 20 - 10 = 10.

D. $\frac{20}{6} -4= 3.333 - 4 = -0.666,$

E. $\frac{1}{6} (20-24) = \frac{1}{6} (-4)= -0.666,$

F. $(20-24)\frac{1}{6} = (-4)\frac{1}{6} = -0.666.$

So the options D, E, and F represent a correct solution to the given equation.

7 0

3 years ago