Answer:
The bases do not have the same area because the volume of the cylinder is not 3 times the volume of the cone, given the same heights.
Step-by-step explanation:
Recall :
V1 = volume of cylinder = πr²h
V2 = volume of a cone = 1/3πr²h
From the diagram, both have height, h of 12
Radius = r
V1 = 2512 in
V2 = 1256 in
From the ratio :
2512 = πr² * 12
1256 = 1/3πr² * 12
12 cancel out as well as r² and π
If the bases have the same area `, then 2512 should be equal to (1256 * 3)
2512 in ≠ 3868 in
|2x-3|=2x-3 ;x≥ 3/2
|2x-3|=-2x+3;x≤3/2
F(x) = (1/2)x + 4
Plug y in for f(x).
y = (1/2)x + 4
Swap x and y.
x = (1/2)y + 4
Solve the equation for y =.
Subtract 4 from both sides.
x - 4 = (1/2)y
Multiply each term 2.
2x - 8 = y
Plug f^-1(x) in for y.
f^-1(x) = 2x - 8
f^-1(4) = 2(4) - 8
f^-1(4) = 0
3750(0.20)=$750
1/5 as a percent is 20% and as a fraction it is 0.20
We have :
s - 39⁰+ s - 9⁰ = s + 29⁰
s + s - s = 29⁰ + 9⁰ + 39⁰
s = 77⁰
Answer: 77⁰
Ok done. Thank to me :>