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natita [175]
2 years ago
6

This is due at 8:00PM please someone help

Mathematics
1 answer:
krek1111 [17]2 years ago
6 0
10. A 11. D 12. A (wasn’t too sure about question 12)
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What are zeros of f(x)=x^2-3x-18. and please explain so I can see if I can understand.
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F(x) = x^2 - 3x - 18

Find the values that when multiplied equal -18 and when added equal -3 (6 and -3)
Plug it into f(x) = (x - 1st value)(x - 2nd value)

f(x) = (x - 6)(x + 3)
0 = (x - 6) (x + 3)

(One of the factors has to equal zero, so set them both equal to zero)

x - 6 = 0
x = 6

x + 3 = 0
x = -3

x = 6, x = -3


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\sf\dfrac{2+5}{13}\rightarrow\dfrac{7}{13}
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