If we draw a rhombus OABC on a coordinate grid with one vertex at the point O (0,0)
and let its height be 1 then (using the Pythagoras theorem) the coordinates of the 4 points will be as follows:-
O = (0,0) , A = (1, 1), B = (sqrt2+ 1 , 1) , C = (sqrt2, 0)
Slope of the diagonal OB = 1 / (sqrt2 + 1)
Slope of the other diagonal AC = - 1 / (sqrt2 - 1)
Product of the slopes = - 1 / ( sqrt2 + 1)(sqrt2 - 1) = -1 / 1 = -1
This proves that the diagonals are perpendicular.
The angles are 72 degrees and 108 degrees.
Explanation:
Angle 1 : Angle 2 = 2 : 3
Angle 1 = 2k
Angle 2 = 3k
Angle 1 + Angle 2 = 180 (supplementary angles)
2k + 3k = 180
5k = 180
k = 36
Angle 1 = 2k = 2 x 36 = 72 degrees
Angle 2 = 3k = 3 x 36 = 108 degrees
Answer:
111100 base 2
Step-by-step explanation:
The conversion of 60 base 10 to base 2
When converting a number from base 10 to base 2, the following steps are taken:
a) The number in base 10 is divided by 2 and the remainder is recorded, this continues until the remainder is less than 2.
b) The remainder from the bottom to the top are arranged so as to get the representation of the number in base 2.
60 base 10 to base 2
60 ÷ 2 = 30 remainder 0
30 ÷ 2 = 15 remainder 0
15 ÷ 2 = 7 remainder 1
7 ÷ 2 = 3 remainder 1
3 ÷ 2 = 1 remainder 1
1 ÷ 2 = 0 remainder 1
The remainder from bottom to top is 111100 base 2.
(60)₁₀ = (111100)₂
Answer:
linear
Step-by-step explanation:
Where is the picture for this problem???
