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2 years ago

Use compatible numbers to find two estimate 478÷12=

2 answers:

6 0

Do 470 divided by 10. That should take you close to the true answer. They are also very compatible since they are easy to divide.

dimulka [17.4K]2 years ago

4 0

Answer:

$478\div 12\approx 48$

Step-by-step explanation:

Given : Expression $478\div 12$

To find : Use compatible numbers to find two estimate of expression ?

Solution :

Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.

478 estimating to nearest whole number is 480.

12 estimating to nearest whole number is 10.

So, $478\div 12=480\div 10$

$\frac{480}{10}=48$

Therefore, When we estimate two number we get the result 48.

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The sum of two numbers is 50. One number is 10 less than three times the other number. What are the two numbers? 25 and 25 45 an

DENIUS [597]

One number is x
other number is 3x-10

x + 3x - 10 = 50
4x = 50 + 10
4x = 60
x = 60/4
x = 15 ← one number

the other number = 3x - 10 = 3*15 - 10 = 35

6 0

3 years ago

The sum of three times the square of a number and -7

Ganezh [65]

Answer:

3x² - 7

Step-by-step explanation:

3 times (number squared) and sum with (-7)

3 times x² and add (-7)

3x² + (-7)

3x² - 7

3 0

2 years ago

The basketball team spends 20 minutes running laps and at least 15 minutes discussing plays. Practice lasts one hour and 45 minu

Allushta [10]

Answer:

x ≤ 75

Step-by-step explanation:

The computation of the inequality function is as follows:

Let us assume the remaining time left for other drills be x

Given that the team spends 20 minutes for running laps

And minimum of 15 minutes for discussing plays

Also practicing for last one hour and 45 minutes

Now as we know that

1 hour = 60 minutes

So total minutes would be

= 60 + 45

= 105 minutes

Total minutes spend by the team is

= 20 + 15

= 35 minutes

So now the remaining time left is

x ≤ 105 - 35

x ≤ 75

8 0

3 years ago

Evaluate 18-2(10+8)/6 squared and please explain how you did it

ICE Princess25 [194]

Answer: 12

Step-by-step explanation:

18−2(10+8)/6

=18−(2)(18)/6

=18−36/6

=18−6

=12

4 0

2 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago