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Svetllana [295]
3 years ago
9

How long would it take me to earn 139.50 of interest at a 6% interest rate if I started with 930

Mathematics
1 answer:
Natali [406]3 years ago
3 0
139.50/55.8=t t=2.5 yrs simple interest
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5 0
3 years ago
Read 2 more answers
Help soon please! I need to get done soon
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Two Decimal places

.9(29.3) = 26.37

18(5.75)= 103.50

Three Decimal places

3.21(2.4) = 7.704

50.7(14.06)= 712.842

Four Decimal places

4.2(.938)= 3.9396

.48(12.19)= 5.8512

8 0
3 years ago
Use the discriminant to determine the nature of the roots of the following questions
soldier1979 [14.2K]

Answer:

the function has two distinct real roots.

Step-by-step explanation:

D=b²-4ac    

D<0 No real roots

D=0 One real root

D>0 Two distinct real root.

    (-5)²-4*1*-3

    25+12

    37

Since D is > than 0, the function has two distinct real roots.

6 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
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