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3 years ago

The perimeter of a rectangle is 15x + 17y. If the length is 7/2x + 7y then find the width of the rectangle.

Mathematics

1 answer:

EastWind [94]3 years ago

5 0

Answer:

84 c. –25 6. 119 7. –28 36 8a. 4 b. 52 LESSON EI.B: ANSWERS 709 Topic EI .... The length is 11 inches, and the width is 7 inches. ... 15x – 10 = 2x + 6 1 5 10. x = 1 11. y = 8x – 5 12. x = y + 8 8 49. .... 5xy 3 – 17x 2y + 8xy + 16x 3y – 7x 10. x 3y 2z – 10x 2y + 14x 2z + 3xy 2 – 25xz 2 LESSON ... 2 > y > –5 F a 4x 3 y 5 4y 3 x 22.

Step-by-step explanation:

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(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
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Parallelograms can be used to prove statements about triangles.<br><br><br> True False

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