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3 years ago

If I owe you $1.76 in overtime pay, you receive $19.50 for each hour of OT. How many hours overtime are you owed?

Mathematics

1 answer:

Lady_Fox [76]3 years ago

6 0

Answer: 0.09 hours

Step-by-step explanation:

You are owed $1.76 in overtime pay.

The hourly rate for overtime is $19.50 per hour.

To find the number of hours owed, you need to divide the amount owed by the amount owed per hour.

The number of hours you are owed is therefore:

= Amount owed / Amount owed per hour

= 1.76 / 19.50

= 0.09 hours

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Anna35 [415]

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3 years ago

The cost of renting a bicycle from Dan's Bike Shop is $2 for 1 hour plus $1 for each additional hour of rental time. Which of th

Vlad [161]

option B

Explanation:

The cost of renting per hour = $2

For 1 hour = $2

For each additional hour, it is $1

For 2 hours = First hour + 1(additional hour)

For 2 hours = $2 + $1(1) = 2+1 = $3

For 3 hours = $2 + $1 (2) = 2+2 = $4

For 4 hours = $2 + $1(3) = 2+3 = $5

The graph which shows this rental cost as 2, 3, 4, 5 is option B

7 0

1 year ago

Can you solve 27,28,39,30,31,32,33,34?

kozerog [31]

Answer:

27. x^7

28. 4x^13

29. 1/f^4

30. x^5

31. 2x^14

32. (4y^3 x^2)^2

33. (2y/x)^6

Step-by-step explanation:

$27. \: \: \frac{ {x}^{ - 1} }{ {x}^{ - 8} } \\ \frac{ {x}^{8} }{ {x}^{1} } \\ {x}^{8 - 1} = {x}^{7} \\$

$28. \: \: \: \frac{ {52x}^{6} }{ {13x}^{ - 7} } \\ \frac{ {52x}^{6} {x}^{7} }{13} \\ {4x}^{6 + 7} = {4x}^{13}$

$29. \: \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\ {f}^{( - 3) +2 + ( - 3) } \\ {f}^{ - 4} \\ \frac{1}{ {f}^{4} } \\$

$30. \: \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\ \frac{ {x}^{9} }{ {x}^{4} } \\ {x}^{9 - 4} = {x}^{5}$

$31. \: \: \frac{ {24x}^{6} }{ {12x}^{ - 8} } \\ \frac{ {24x}^{6} {x}^{8} }{12} \\ {2x}^{6 + 8} = {2x}^{14} \\$

$32. \: \: \frac{ {3x}^{2} {y}^{ - 3} }{ {12x}^{6} {y}^{3} } \\ \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3} {y}^{3} } \\ \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} } \\ \frac{ {x}^{ - 4} }{ {4y}^{6} } \\ \frac{1}{ {4y}^{6} {x}^{4} } = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }$

$33. \: \: {( {2x}^{3} {y}^{ - 3}) }^{ - 2} \\ {2x}^{3 \times - 2} {y}^{ - 3 \times - 2} \\ {2x}^{ - 6} {y}^{6} \\ \frac{ {2y}^{6} }{ {x}^{6} } \\ {( \frac{2y}{x} )}^{6} \\$