3 years ago

What are the roots of y = x2 – 3x - 10? 0 -3 and -10 0-2 and 5 2 and -5 3 and 10

Mathematics

1 answer:

nata0808 [166]3 years ago

5 0

Answer:

roots: -2 and 5

Step-by-step explanation:

What are the roots of y = x2 – 3x - 10?

we see...

factor -10 .... using the X-method.

-10 = 2 * -5

where 2 + -5 = -3

y = (x +2)(x - 5)

roots are -2 and 5

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Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle

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Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

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$Area \ \ \alpha \ \ r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\ \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\ \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\ \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\ \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\$