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jeyben [28]
4 years ago
10

Which proportion models this problem?

Mathematics
1 answer:
oksano4ka [1.4K]4 years ago
4 0
The proportion that models the problem would be x/850 = 11/17. :)
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The area rug in your living room is 5 feet longer than it is wide. If the rug is
Romashka-Z-Leto [24]

Answer:

length = 17 ft and width = 12 ft

Step-by-step explanation:

The rug is rectangular .

Let

width = a

length = a + 5

Area of the rug = a × (a + 5) = a² + 5a

The rug is always placed 2 ft from the wall. The illustration describes a rectangle place into another. The space between the rug and the wall is 100 ft².  

The living room

length = a + 5 + 2 + 2= a + 9

width  = a + 2 + 2 = a + 4

area = (a + 9)(a + 4) = a² + 4a + 9a + 36 = a² + 13a + 36

a² + 13a + 36 - (a² + 5a) = 100

a² + 13a + 36 - a² - 5a = 100

8a + 36 = 100

8a = 100 - 36

8a = 64

a = 64/8

a = 8

Dimension of the living room

length = a + 9

length = 8 + 9 = 17 ft

width  = a + 4

width = 8 + 4 = 12 ft

length = 17 ft and width = 12 ft

4 0
3 years ago
(0,-1) and (3,-5)<br> Write in point slope form an equation of the line through each pair of points
natali 33 [55]

Answer:

y=\frac{-4}{3}x-1

Step-by-step explanation:

slope:

\frac{y2-y1}{x2-x1} \\=\frac{-5+1}{3}=\frac{-4}{3}

point slope formula:

y-y1=m(x-x1)

y-(-1)=\frac{-4}{3}(x-0)

y+1=\frac{-4}{3}x

y=\frac{-4}{3}x-1

4 0
3 years ago
Boyle’s law states that the volume of gas varies inversely with applied pressure. Suppose the pressure on 60 cubic meters of gas
sergij07 [2.7K]

Answer: 20m³

Step-by-step explanation:

From the statement

V <> 1/p --------------------- 1

V = k/p --------------------- 2

K. = VP ---------------------- 3

V = 60 , p = 1

To find k which is a constant, we put those values in equation 3

K = 60 x 1

= 60.

Now from the second statement

V = k/p where p is 3

Therefore,

V = 60/3

= 20m³

6 0
3 years ago
What is the center of the data number of laps around a track?​
notka56 [123]

Answer:

The real answer is

Step-by-step explanation:

2,i just took the test

6 0
4 years ago
If your lawnmower uses 1/3 of a gallon of gas to cut grass for one hour and you have 5/6 gallins of gas how long can you cut the
Eddi Din [679]

Answer:

Answer is 2 hours

Step-by-step explanation:

You have to change 1/3 to 2/6

5÷2=2.5

8 0
3 years ago
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