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Akimi4 [234]
3 years ago
15

Computer keyboard failures can be attributed to electrical defects or mechanical defects. a repair facility currently has 25 fai

led keyboards 6 of which have electrical defects and 19 of which have mechanical defects. how many ways are there to randomly select 5 of these keyboards for a thorough inspection (without regard to order)?
Computers and Technology
1 answer:
Mariulka [41]3 years ago
5 0
You are going to select 5 keyboards, from a set of 25 defective keyboards. When you select the first keyboard it may be have either electrical deffects or mechanical deffect, this is two possibilities. The same happens with the second, third, fourth and fifth selection. Then  each selection has 2 different possibilities, and the number of possibilities are: 2*2*2*2*2 = 32.

But that is considering that the order matters. This is that it is different that the first has electrical deffects and the others have mechanical defects than the second has mechanical electrical deffects and the other has mechanical deffects.

If you the order is not relevant, then the only different outcomes are:

1) 5 with electrical deffects
2) 4 with electrical deffects and 1 with mechanical deffects
3) 3 with electrical deffects and 2 with mechanical deffects
4) 2 with electrical deffects and 3 with mechanical deffects
5) 1 with electrical deffects and 4 with mechanical deffects
5) 5 with mechanical deffects.

In this case the answer is 6 different ways.

Answer: 6 
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Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

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        for (z = 0; z <= 100; z++)//defining for loop to z value

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           {

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}

Output:

Please find the attached file.

Explanation:

In the above-given code four integer variable "x,y,z, and c" is declared, in which "x,y, and z" is used in the for loop with the if conditional statement that checks the given condition and prints the solution and the "c" variable is used to counts the number of solution, and at the last, it uses the print method to print its values.  

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