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Lana71 [14]
3 years ago
13

Trading stock or selling stock, selling real estate for profit, and selling other assets that gain value over time.

Computers and Technology
1 answer:
Andrei [34K]3 years ago
3 0

Answer:

D is reasonable

Explanation:

You might be interested in
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
An associate is seeking advice on which device to purchase for a friend who is a business owner. The friend needs the ability to
spayn [35]

The best recommendation in the mentioned scenario would be a smart watch.

Answer: Option A.

Explanation:

The best device for a business owner who needs an access to chat as well as to be in touch with the home office would be a smart watch. A smart watch is similar to a mobile device, which is worn on a wrist and which has a touchscreen display.

The benefits of smart watch are numerous. It makes us updated about everything without using our smartphone. The smart watch will help the business owner to engage with others and to handle his work at the same time.

5 0
3 years ago
Complete the function ending_time that determines the final clock time after a task has been completed. The function takes three
Ivanshal [37]

Answer:

  1. def ending_time(hour, minutes, seconds, work_time):
  2.    if((seconds + work_time) // 60 > 0):
  3.        minutes = minutes + (seconds + work_time) // 60
  4.        seconds = (seconds + work_time) % 60    
  5.        if(minutes // 60 > 0):
  6.            hour = hour + (minutes // 60)
  7.            minutes = minutes % 60
  8.    else:
  9.        seconds = seconds + work_time  
  10.    return str(hour) + ":" + str(minutes) + ":" + str(seconds)
  11. print(ending_time(2,30,59, 12000))

Explanation:

The solution code is written in Python 3.

Firstly create a function ending_time that takes the four required input parameters.

Next, create an if statement to check if the numerator of (seconds + work_times) divided by 60 is over zero. If so, increment the minute and reassign the remainder of the seconds to the variable (Line 2-4).

Next, create another if statement again to check if the numerator of (current minutes) divided by 60 is over zero, if so increment the hour and reassign the remainder of the minutes to the variable (Line 6-8)

Otherwise, just simply add the work_time to the current seconds

At last return the time output string (Line 12).

8 0
3 years ago
Match each feature of the E publishing as an advantage a disadvantage a threat or an opportunity
natta225 [31]

Answer:

E-publishing is also known as digital publishing or online publishing.It means to publish the content in electronic form.It is growing rapidly.It consist digital publication of e-books,digital magazines that can be read on a screen.

<u>Explanation:</u>E-publishing is very convenient.We do not have to keep  large number of books on the shelves.E-books are best during travelling because we need not to carry heavy luggage of books.E-books are cheaper than paperbacks.

E-publishing can allow the authors  to reach large number of readers.Electronic contents are very well updated.Electronic books are environment friendly.It saves wastage of papers and hence cutting of trees.

Besides above advantages there are some disadvantages of E-publishing:

There are more responsibilities in E-publishing.Chances of copyright infringement can be there.

Profits are very low in case of e-publishing.It is not easy to earn money through this method.

Quality of printed books is much better than e-books.

So we can say that e-publishing has it's own advantages and disadvantages.

3 0
4 years ago
Write code that prints: Ready! firstNumber ... 2 1 Run!
motikmotik

Answer:

The program to this question can be defined as follows:

Program:

num=int(input("Enter any number: ")) #defining variable num, that take value from user

val=0; #defining variable val

for i in range(num): #defining loop to calculate value in decreasing order

   val=num-i; #holding value in variable

   print(val) #print value

Output:

Enter any number: 3

3

2

1

Explanation:

In the above-given code, a variable "num" is declared, that uses input function to take value from the user end, in the next line a "val" variable is defined, that calculates values and print it in decreasing order.

  • In the next step, a for loop is declared, inside the loop a "val" variable uses num and loop variable "i" to calculate the value in decreasing order.
  • In the last print method is used that prints "val" variable value.
3 0
3 years ago
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