Dimension of one of the floors of one room that David wants to install tiles is 18feet long by 12 feet wide
Then
Area of the above room = 18 * 12 square feet
= 216 square feet
Dimension of the floor of the other room that David wants to install tiles is 24 feet long and 16 feet wide
Then
Area of the other room = 24 * 16 square feet
= 384 square feet
Then
The total square feet of the
rooms that David wants to install tiles = 216 + 384
= 600 square feet
Cost of the tile that covers 1 square feet = $5
Cost of the 4 tiles that cover 4 square feet = $17
Then
Area that can be covered with 4 square feet of tiles = 600/4 square feet
= 150 square feet
Minimum cost of covering
the two rooms that David wants to install tiles = 150 * 17 dollars
= 2550 dollars
So the minimum cost of installing the tiles on the two floors of David's two rooms is $2550. I hope the procedure is simple enough for you to understand.
Answer: 4 hours
Step-by-step explanation:
okay so you have to know your times tables 2*4=8 so 20*40=80 then if he paid a tip of 10$ that would equal $90 witch is what he paid.
6(x-1)
4x
X = 6*x-1*6/6x-6=4x
X= -6=4x-6x
X=-6=-2x
Value of x Is 3
-- Candy takes 57 minutes to do the whole job ==>
She does 1/57 of the job every minute.
-- Tim takes 114 minute to do the whole job ==>
He does 1/114 of the job every minute.
-- If they work together, they do (1/57 + 1/114) of the job every minute.
We have to add those fractions.
The least common denominator is 114.
(1/57 + 1/114)
= (2/114 + 1/114)
= 3/114 = 1/38 .
Working together, Candy and Tim do 1/38 of the job every minute.
So it takes them 38 minutes to do the whole job together.
