An office manager booked 61 airline tickets. He booked 8 more tickets on Airlines A than Airlines B. On Airlines C, he booked 5
more than twice as many tickets as on Airlines B. How many tickets did he book on each airline?
1 answer:
Answer:
B = 12
A = 20
C = 29
Step-by-step explanation:
A = tickets on airline A
B = A-8
C = 2B +5
Total = 61
A + B+ C = 61
Taking B = A -8 and writing in terms of A
A = B+8
Replacing A and C in the equation A + B+ C = 61
( B+8) + B + 2B +5 = 61
Combining like terms
4B +13 = 61
Subtract 13 from each side
4B =13-13 = 61-13
4B =48
Divide by 4
4B /4 = 48/4
B = 12
A = B +8 = 12+8 = 20
C = 2B +5 = 2*12+5 = 24+5 = 29
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