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RUDIKE [14]
2 years ago
9

Distribute a negative -7.1h-(-2k-1)

Mathematics
1 answer:
Andrew [12]2 years ago
3 0

Answer:

<h2>=-7.1h+2k+1</h2>

Step-by-step explanation:

-7.1h-(-2k-1)\\-\left(-2k-1\right):\quad 2k+1\\=-7.1h+2k+1

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3 years ago
Write an equation for line N
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Answer:

y=x-1

Step-by-step explanation:

6 0
2 years ago
State the converse, contrapositive, and inverse of each of these conditional statements a) If it snows tonight, then I will stay
marissa [1.9K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

  • The rule for Converse is: Interchange the two statements.
  • The rule for Inverse is: Negative both statements.
  • The rule for Contrapositive is: Negative both statements and interchange them.

Part (A) If it snows tonight, then I will stay at home.

Here p is If it snows tonight, and q is I will stay at home.

Converse: If I will stay at home then it snows tonight.

q \rightarrow p

Inverse: If it doesn't snows tonight, then I will not stay at home.

\sim p \rightarrow \sim q

Contrapositive: If I will not stay at home then it doesn't snows tonight.

\sim q \rightarrow \sim p

Part (B) I go to the beach whenever it is a sunny summer day.

Here p is I go to the beach, and q is it is a sunny summer day.

Converse: It is a sunny summer day whenever I go to the beach.

q \rightarrow p

Inverse: I don't go to the beach whenever it is not a sunny summer day.

\sim p \rightarrow \sim q

Contrapositive: It is not a sunny summer day whenever I don't go to the beach.

\sim q \rightarrow \sim p

Part (C) When I stay up late, it is necessary that I sleep until noon.

P is I sleep until noon and q is I stay up late.

Converse: If I sleep until noon, then it is necessary that i stay up late.

q \rightarrow p

Inverse: When I don't stay up late, it is necessary that I don't sleep until noon.

\sim p \rightarrow \sim q

Contrapositive: If I don't sleep until noon, then it is not necessary that i stay up late.

\sim q \rightarrow \sim p

7 0
2 years ago
Some Math i can’t helppp
mezya [45]

Annually The amount after 10 years = $ 7247.295

quarterly compound after 10 years = $7393.5

Continuously interest =$7,419

Given:

P = the principal amount

r = rate of interest

t = time in years

n = number of times the amount is compounding.

Principal =  $4500

time= 10 year

Rate = 5%

To find: The amount after 10 years.

The principal amount is, P = $4500

The rate of interest is, r = 5% =5/100 = 0.05.

The time in years is, t = 10.

Using the quarterly compound interest formula:

A = P (1 + r / 4)4 t

A= 4500(1+.05/4)40

A= 4500(4.05/4)40

A= 4500(1.643)

Answer: The amount after 10 years = $7393.5

Using the Annually  compound interest formula:

A = P (1 + r / 100) t

A= 4500(1+5/100)10

A= 4500(105/100)10

Answer: The amount after 10 years = $ 7247.295

Using the Continuously  compound interest formula:

e stands for Napier’s number, which is approximately 2.7183

A=Pex^{rt} \\A=4500(e)^{.5} \\A= 4500(2.71)^{.5}

A= $2,919

Answer: The amount after 10 years = $4500+$2,919=$7,419

More details :brainly.com/question/13307568

#SPJ9

7 0
1 year ago
Expand &amp; simplify <br> 5<br> (<br> p<br> +<br> 6<br> )<br> −<br> 5<br> (<br> p<br> −<br> 2<br> )
HACTEHA [7]

Answer: 0p + 40

Step-by-step explanation:

5p + 30 - 5p + 10

0p + 40

8 0
2 years ago
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