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OLga [1]
3 years ago
8

If you're good at math i'd love some help :)

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
7 0

Answer:

x = 10, and x = - 2

Step-by-step explanation:

This equation has two solutions, as it resembles a quadratic equation. When graphed it will be a parabola, and hence intersects the x - intercept at two points, giving us two solutions.

Let's start by expanding the equation,

(x - 4)² - 28 = 8,

(x - 4)² = 28 + 8,

(x - 4)² = 36,

x - 4 = √36, and x - 4 = - √36

x - 4 = 6, and x - 4 = - 6

Solution(s) : x = 10, and x = - 2

Blizzard [7]3 years ago
5 0

Answer:

x = 10     x = -2

Step-by-step explanation:

(x-4)^2 -28 = 8

This is a parabola on the left and a constant line on the right.  The parabola will cross the line twice, so there will be two solutions

see attached

Add 28 to each side

(x-4)^2 -28+28 = 8+28

(x-4)^2  = 36

Take the square root of each side

sqrt((x-4)^2) = ±sqrt(36)

x-4 = = ±6

Add 4 to each side

x-4+4 = 4±6

x = 4+6    x = 4-6

x = 10     x = -2

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ValentinkaMS [17]
Question 1:

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(A) find F(x) for the indicated values of x, if possible
dem82 [27]

Answer:

A) The indicated values of F(x) for x=-3 and x=5 are F(-3)=-27  and F(5)=125

B) The domain of f is the set of all real numbers

Step-by-step explanation:

Given that the function F is defined by

F(x)=x^3 for x=-3,5

A) To find F(x) for the indicated values of x :

Given F(x)=x^3 for x=-3,5

  • Put x=-3 in the given function

F(-3)=(-3)^3

=(-3)\times (-3)\times (-3)

=-27

Therefore F(-3)=-27

  • Put x=5 in the given function

F(5)=(5)^3

=(5)\times (5)\times (5)

=125

Therefore F(5)=125

The indicated values of F(x) for x=-3 and x=5 are F(-3)=-27  and F(5)=125

B) To find the domain of f :

The domain of the f in the given expression is the set of all real numbers except where the expression x^3 is undefined. In this case, there is no real number that makes the expression undefined.

The domain of f is the set of all real numbers

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3 years ago
A packet of biscuits has a mass of 1 1/3 kg. Jason eats 2/5 of the packet. What is the mass of biscuits left?
BabaBlast [244]
11 / 3 = 55 / 15;
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