Answer:
12:06
Step-by-step explanation:
Gwendolyn Logan is not happy with you cheating.
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
Answer:
(5 x + 4) (x - 1)
Step-by-step explanation:
Factor the following:
x (5 x + 4) - (5 x + 4)
Hint: | Pull a common factor out of x (5 x + 4) - (5 x + 4).
Factor 5 x + 4 out of x (5 x + 4) - (5 x + 4), resulting in (5 x + 4) (x - 1):
Answer: (5 x + 4) (x - 1)