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2 years ago

Four times a number, plus 6 equals 58. What is the equation to represent this situation and what is the number?"

Mathematics

2 answers:

Oksanka [162]2 years ago

4 0

Answer: $x = 13$

Step-by-step explanation:

Let the unknown number be $x$ , then from the question :

$4x + 6 = 58$

subtract 6 from both sides , we have

$4x = 58 - 6$

$4x = 52$

divide through by 4

$x = 52/4$

$x = 13$

algol132 years ago

3 0

Answer:

X = 13

Step-by-step explanation:

4x+6=58

4x+6-6=58-6

4x / 4 =52/ 4

x=13

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in parallelogram abcd diagonals ac and bd intersect at point l . If Al= x-2 and ac =3x-16 , then which of the following represen

TiliK225 [7]

Answer:

The length of CI is 10 units.

Step-by-step explanation:

It is given that ABCD is a parallelogram and diagonals AC and BD intersect at point I.

The diagonals of a parallelogram bisect each other.

$AI=CI$

$AC=AI+CI$

$AC=AI+AI$ $[\because AI=CI]$

$AC=2AI$

$3x-16=2(x-2)$

$3x-16=2x-4$

$3x-2x=16-4$

$x=12$

The value of x is 12.

$CI=AI=x-2=12-2=10$

Therefore the length of CI is 10 units.

4 0

2 years ago

Factor completely. y2 - xy - 56x2

aliina [53]

For this case we have the following expression:
y2 - xy - 56x2
Rewriting we have the factored expression, which is given by:
(7x + y) (y-8x)
Checking we have:
7xy - 56x ^ 2 + y ^ 2 - 8xy
y ^ 2 - xy - 56x ^ 2 (OK)
Answer:
The factored expression is given by:
y2 - xy - 56x2 = (7x + y) (y-8x)

5 0

2 years ago

Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim

vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

$2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}$