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miv72 [106K]
3 years ago
5

NEED HELP IN THREE MATH QUESTIONS

Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0
I can'r see the problem
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PLEASE HELP ME WITH MY MATH
emmainna [20.7K]

Oh my gosh,

I need an answer for that as well..

4 0
2 years ago
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FMFWE,KFJWKJWKLEJWLKERJWLKRJLWKERJLWRJLWRJLWERJWERJWLKRJWERJWLE
max2010maxim [7]

Step-by-step explanation:

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3 0
2 years ago
Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.
KengaRu [80]

Answer:

X=6 and Y=3

Step-by-step explanation:

Use SOHCAHTOA, SOH, Sin=Opposite/Hypotenuse, Therefore Sin60°=(3√3)/x ; Xsin60°=3√3 and Sin60° without using 4figuretable or calculator is √3/2, Now x=3√3 ÷√3/2 ;. therefore X=3√3×2/√3= 6. X=6 . Using Pythagoras theorem, 6²={(3√3)² +y²}. Y²= 36-27=9. Y=√9, Y=3. Therefore X=6 and Y=3.

7 0
3 years ago
The temperature was 78°F at 3 P.M. Each hour for
polet [3.4K]

Answer:

  66 °F

Step-by-step explanation:

At 4 P.M., the temperature had decreased by 3° from the temperature at 3 P.M., so was ...

  4 P.M. temp = 78 °F -3° = 75 °F

This was repeated until 7 P.M.

  5 P.M. temp = 75 °F -3° = 72 °F

  6 P.M. temp = 72 °F -3° = 69 °F

  7 P.M. temp = 69 °F -3° = 66 °F

The temperature at 7 P.M. was 66 °F.

__

Of course the repeated subtraction can be simplified using multiplication. The subtraction of 3° four times is equivalent to the subtraction of . . .

  (3°)(4) = 12°

That is, the temperature at 7 P.M. is ...

  78 °F -3°×4 = 78 °F -12° = 66 °F

6 0
2 years ago
Solve for b. <br><br> 3a + 2b = c
Licemer1 [7]
B=(c-3a)/2
Should be the equation you get

5 0
3 years ago
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