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vodka [1.7K]
3 years ago
12

Please solve these questions on the topic of exponents

Mathematics
1 answer:
galina1969 [7]3 years ago
6 0

Answer/Step-by-step explanation:

Recall: x^{-a} = \frac{1}{x^a}

a. 4^{-3} = \frac{1}{4^3} = \frac{1}{64}

b. 13^{-2} = \frac{1}{13^2} = \frac{1}{169}

c. (-3)^{-2} = \frac{1}{-3^2} = \frac{1}{9}

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Solve for x. You must write your answer in fully simplified form.<br> -12x = -10
satela [25.4K]

Answer:

0.83333333333

Step-by-step explanation:

you divide -12 both sides but its a really odd number

5 0
4 years ago
Read 2 more answers
A piece of timber is x cm long. 7 cm is cut off. How much is left?
anygoal [31]

Answer:

x-7>0

Straight answer: x-7

Step-by-step explanation:

Assuming that the timber is X cm long and 7cm was cut off, there remaining amount is x - 7cm. In order for 7cm to be cut off, the timber must have been > 7cm long => x > 7 => x - 7 > 0

3 0
3 years ago
Luis is finding 9-6+2. Find his mistake and correct it
valina [46]
Luis is finding 5 because 9 minus 6 is 3. 3 plus 2 equal 5 easy
3 0
4 years ago
4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
3 years ago
How to solve 1-(-8)- 12/-3
Fudgin [204]

Answer:

ok so the answer is 13

Step-by-step explanation:

to solve you..

PEMDAS

PLEASE EXUSE MY DEAR AUNT SALLY

1-(-8)-12/-3

1-(-8)+4

1+8+4

9+4

13

!

HOPE THIS HELPED YA

4 0
3 years ago
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