Answer:
The answer is 113.10 square meters. Calculate the area of 6 meter circle and you get 113.10. Have a great day!!!
Step-by-step explanation:
![\bf \int [11\ ln\left( \sqrt[3]{x} \right)]dx\qquad \begin{cases} ln\left( \sqrt[3]{x} \right)\implies ln\left( x^{\frac{1}{3}} \right) \\ \quad \\ \frac{1}{3}ln(x) \end{cases}\qquad thus \\ \quad \\\\ \quad \\ \int [11\ ln\left( \sqrt[3]{x} \right)]dx\implies \int[11\cdot \frac{1}{3}ln(x)]dx\impliedby \textit{scalars to the left} \\ \quad \\ 11\cdot \frac{1}{3}\int[ln(x)]dx\implies \cfrac{11}{3}\int[ln(x)]dx](https://tex.z-dn.net/?f=%5Cbf%20%5Cint%20%5B11%5C%20ln%5Cleft%28%20%5Csqrt%5B3%5D%7Bx%7D%20%5Cright%29%5Ddx%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Aln%5Cleft%28%20%5Csqrt%5B3%5D%7Bx%7D%20%5Cright%29%5Cimplies%20ln%5Cleft%28%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Cright%29%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Cfrac%7B1%7D%7B3%7Dln%28x%29%0A%5Cend%7Bcases%7D%5Cqquad%20thus%0A%5C%5C%20%5Cquad%20%5C%5C%5C%5C%20%5Cquad%20%5C%5C%0A%5Cint%20%5B11%5C%20ln%5Cleft%28%20%5Csqrt%5B3%5D%7Bx%7D%20%5Cright%29%5Ddx%5Cimplies%20%5Cint%5B11%5Ccdot%20%5Cfrac%7B1%7D%7B3%7Dln%28x%29%5Ddx%5Cimpliedby%20%5Ctextit%7Bscalars%20to%20the%20left%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A11%5Ccdot%20%5Cfrac%7B1%7D%7B3%7D%5Cint%5Bln%28x%29%5Ddx%5Cimplies%20%5Ccfrac%7B11%7D%7B3%7D%5Cint%5Bln%28x%29%5Ddx)
and I'm pretty sure you know what that is
Answer:
x = 10
Step-by-step explanation:
Since the two triangles are congruent, ∠B ≅ ∠E
50 = 5x
x = 10
Answer:
C
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
given the 2 equations
y - 4x = 12 → (1)
2 - y = 2(x + 2)² → (2)
rearrange (1) expressing y in terms of x
y = 12 + 4x
Simplify (2) by expanding factor and substituting y = 12 + 4x
2 - (12 + 4x) = 2(x² + 4x + 4)
2 - 12 - 4x = 2x² + 8x + 8
- 10 - 4x = 2x² + 8x + 8 ← rearrange into standard form
add 10 + 4x to both sides
2x² + 12x + 18 = 0 ← in standard form
divide through by 2
x² + 6x + 9 = 0
(x + 3)(x + 3) = 0 ⇒ (x + 3)² = 0 ⇒ x = - 3
Point of intersection = (- 3, 0 ) → B
