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Fittoniya [83]
3 years ago
12

8. Graph the following equation: y = x2 + 4x - 5

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

Given: y = x2 + 4x – 5

Find the following

y-intercept

x-intercepts or the zeros of the functions or roots

graph of the function, given vertex is at (-2, -9)

Solve the system of linear equations      – x + 6y = 8        2x + 5y = 3

Write the names of curves, given their equations:  

x2/16 + y2/9 = 1

3y = 2x + 5

(x - 5)2 + (y + 6)2 = 25

x2/16 – y2/25 = 1

y = 2x2 + 10x + 25

Write down the first five terms of the arithmetic progression with the first term 8 and common difference 7, then find the 17th

Write down the first five terms of the geometric progression with the first term 3 and common ratio 2, then find the 17th

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How to improve in math?
Arte-miy333 [17]
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7 0
3 years ago
Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi
maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is y=\frac{8+-10}{2}=-1

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed \frac{2}{3} of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

  is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

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I think the answer might be C i hope this helps you
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