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Dafna1 [17]
3 years ago
12

Choose the best answer from the four choices given. You may use scratch

Mathematics
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

The answer is B.

Step-by-step explanation:

Instead of solving each equation, simply think about it alternatively.

Recall that quadratic equations can also be written as: (x-a)(x-b), where a and b are the solutions.

We know that 1 and -3 are solutions, so we can substitute them in for a and b.

Thus, we have:

(x-(1))(x-(-3))

(x-1)(x+3)

Now, expand:

x^2+3x-x-3

x^2+2x-3

The answer is B.

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3 years ago
I really need help with this problem!!
MAXImum [283]

1.

4

2.

11>-2 \underbrace{\implies}_{+3} 14>1 \underbrace{\implies}_{+3} 17>4\underbrace{\implies}_{+(-4)} 13>0

3.

-2

4.

-4

Comments:

We can see that as long as we add/subtract any value to both sides nothing happens: true statements remain true and false statements remain false. But if we multiply or divide by negative values, false statements become true and true statements become false. That why, when you multiply or divide an inequality by a negative number, you should also flip the inequality sign. For example, if we start with the true inequality

-2

If we multiply both sides by -2 we have to flip the sign as well:

4>-2

And the inequality will remain true.

5 0
3 years ago
Mrs Grey is buying decorative ribbon of three different colors: blue, silver, and yellow. Blue ribbon is sold in rolls of 15 met
olganol [36]

Answer:

4 rolls of blue ribbon,

5 rolls of silver ribbon,

3 rolls of yellow ribbon.

Step-by-step explanation:

We have been given that Mrs Grey is buying decorative ribbon of three different colors: blue, silver, and yellow. Blue ribbon is sold in rolls of 15 meters, silver is sold in rolls of 12 meters, and yellow comes in rolls of 20 meters.

As Mrs. Grey needs to have same length of each ribbon, so we will find the least common multiple of 15, 12 and 20.

Multiples of 15 are: 15, 30, 45, 60, 75, 90,...

Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,...

Multiples of 20 are: 20, 40, 60, 80,100,...

We can see that 60 is the least common multiple of 15, 12 and 20.

\text{The smallest number of rolls of blue ribbon}=\frac{60}{15}=4

Therefore, Mrs. Grey should buy 4 rolls of blue ribbon.

\text{The smallest number of rolls of silver ribbon}=\frac{60}{12}=5

Therefore, Mrs. Grey should buy 5 rolls of silver ribbon.

\text{The smallest number of rolls of yellow ribbon}=\frac{60}{20}=3

Therefore, Mrs. Grey should buy 3 rolls of yellow ribbon.

3 0
4 years ago
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