Question

If f(x) = 3/x+2 -sqrt x-3. complete the following statement. Round to the nearest hundredths.

Answer 1

Assuming you mean $f(x)=\frac{3}{x+2}-\sqrt{x-3}$

subsitute
$f(x)=\frac{3}{x+2}-\sqrt{x-3}$
$f(7)=\frac{3}{7+2}-\sqrt{7-3}$
$f(7)=\frac{3}{9}-\sqrt{4}$
$f(7)=\frac{1}{3}-2$
$f(7)=\frac{1}{3}-\frac{6}{3}$
$f(7)=\frac{-5}{3}$
f(7)≈1.6666
round
f(7)=1.67

Answer 2

Answer:

-1.67

Step-by-step explanation:

We are given  that

$f(x)=\frac{3}{x+2}-\sqrt{x-3}$

We have to find the value of f(7).

Substitute x=7

Then, we get

$f(7)=\frac{3}{7+2}-\sqrt{7-3}$

$f(7)=\frac{3}{9}-\sqrt4$

$f(7)=\frac{1}{3}-2$

$f(7)=\frac{1-6}{3}=-\frac{5}{3}=-1.67$

Hence, f(7)=-1.67