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jeka57 [31]
3 years ago
8

Kevin said that if you triple his age the result will be 1 less than his mother age

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0
Basically, this problem is saying that if you multiply x by 3, then you will get a number that is one less than y. So, if you switch that around a bit, then the problem is saying that if you subtract 3x from y, you'll get 1. 

Your final answer should be y - 3x = 1.
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Mary makes trail mix with bulk nuts and dried fruit. She spends $4.50 on the dried fruit. Mixed nuts cost $2.50 per pound. She h
AnnyKZ [126]

Answer: 3 pounds

Step-by-step explanation: 12 - 4.50 = 7.50 7.50/2.50=3

4 0
3 years ago
Please help me I will give brainiest.
Natali [406]
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7 0
3 years ago
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Write the expression that appears under the radical symbol in the quadratic formula. what is the quality called? what can it be
ira [324]
This expression is called the Discriminant, also shown as Δ.
It is equal to b² - 4ac. This is a very important part of the quadratic formula as it determines whether x will have two values, one repeated value or no real values. Here are a few examples.

a) x² - 2x - 1. a is equal to 1 since 1x² = x². b = -2, c = -1
The discriminant will be (-2)² - 4×1×-1 = 4 + 4 = 8.
Since Δ > 0, there are two x values. Graphed, the parabola sinks below the x axis.

b) x². a = 1, b = 0 (0x = 0), c = 0
The discriminant will be 0² - 4×1×0 = 0 - 0 = 0.
Since Δ = 0, there is only one x value. Graphed, the parabola touches the x axis at only one point.

c) x² + 1. a = 1, c = 1.
The discriminant will be 0² - 4×1×1 = 0 - 4 = -4
Since Δ < 0, there are no real x values. Graphed, the parabola floats above the x axis.

Hope this helps!
8 0
2 years ago
Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx
Soloha48 [4]

Answer:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

Step-by-step explanation:

For this case we need to find the following integral:

\int x(8-x)^{3/2}dx

And for this case we can use the substitution u = 8-x from here we see that du = -dx, and if we solve for x we got x = 8-u, so then we can rewrite the integral like this:

\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)

And if we distribute the exponents we have this:

\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du

Now we can do the integrals one by one:

\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C

And reordering the terms we have"

\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C

And rewriting in terms of x we got:

\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C

And that would be our final answer.

8 0
2 years ago
I need the product of a^4xa^6
emmainna [20.7K]
A^4 * a^6

exponent rule : x^y * x^z = x^(y + z)

so, a^4 * a^6 = a^(4 + 6) = a^10
3 0
3 years ago
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